Solve (1v-2x)(6-2x)=12

$$( 1 v - 2 x ) ( 6 - 2 x ) = 12$$

Solve for v

$$v=-\frac{2\left(x^{2}-3x-3\right)}{3-x}$$

$$x\neq 3$$

Steps for Solving Linear Equation

Use the distributive property to multiply 1v-2x by 6-2x.

$$6v-2vx-12x+4x^{2}=12$$

Add 12x to both sides.

$$6v-2vx+4x^{2}=12+12x$$

Subtract 4x^{2} from both sides.

$$6v-2vx=12+12x-4x^{2}$$

Combine all terms containing v.

$$\left(6-2x\right)v=12+12x-4x^{2}$$

Divide both sides by 6-2x.

$$\frac{\left(6-2x\right)v}{6-2x}=\frac{12+12x-4x^{2}}{6-2x}$$

Dividing by 6-2x undoes the multiplication by 6-2x.

$$v=\frac{12+12x-4x^{2}}{6-2x}$$

Divide 12+12x-4x^{2} by 6-2x.

$$v=\frac{2\left(3+3x-x^{2}\right)}{3-x}$$

Solve for x

$$x=\frac{-\sqrt{v^{2}-12v+84}+v+6}{4}$$

$$x=\frac{\sqrt{v^{2}-12v+84}+v+6}{4}$$