Solve (1-7x^3)^2

$$( 1 - 7 x ^ { 3 } ) ^ { 2 }$$

Expand

$$49x^{6}-14x^{3}+1$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(1-7x^{3}\right)^{2}.

$$1-14x^{3}+49\left(x^{3}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$1-14x^{3}+49x^{6}$$

Evaluate

$$\left(1-7x^{3}\right)^{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(1-7x^{3}\right)^{2}.

$$1-14x^{3}+49\left(x^{3}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$1-14x^{3}+49x^{6}$$