Solve (1-4)^3+sqrt[3]{4*(-2)}+0.overline{6}=

$$( 1 - 4 ) ^ { 3 } + \sqrt[ 3 ] { 4 \cdot ( - 2 ) } + 0 . \overline { 6 } =$$

Evaluate

$$-29$$

Solution Steps

Subtract 4 from 1 to get -3.

$$\left(-3\right)^{3}+\sqrt[3]{4\left(-2\right)}+0$$

Calculate -3 to the power of 3 and get -27.

$$-27+\sqrt[3]{4\left(-2\right)}+0$$

Multiply 4 and -2 to get -8.

$$-27+\sqrt[3]{-8}+0$$

Calculate \sqrt[3]{-8} and get -2.

$$-27-2+0$$

Subtract 2 from -27 to get -29.

$$-29+0$$

Add -29 and 0 to get -29.

$$-29$$

Factor

$$-29$$