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1-2\sqrt{3}+\left(\sqrt{3}\right)^{2}-2\left(1-\sqrt{3}\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(1-\sqrt{3}\right)^{2}.
1-2\sqrt{3}+3-2\left(1-\sqrt{3}\right)
The square of \sqrt{3} is 3.
4-2\sqrt{3}-2\left(1-\sqrt{3}\right)
Add 1 and 3 to get 4.
4-2\sqrt{3}-2+2\sqrt{3}
Use the distributive property to multiply -2 by 1-\sqrt{3}.
2-2\sqrt{3}+2\sqrt{3}
Subtract 2 from 4 to get 2.
2
Combine -2\sqrt{3} and 2\sqrt{3} to get 0.