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\left(\frac{1}{3}\right)^{2}+\sqrt{1-\frac{7}{8}}-\frac{11}{18}
Subtract \frac{2}{3} from 1 to get \frac{1}{3}.
\frac{1}{9}+\sqrt{1-\frac{7}{8}}-\frac{11}{18}
Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.
\frac{1}{9}+\sqrt{\frac{1}{8}}-\frac{11}{18}
Subtract \frac{7}{8} from 1 to get \frac{1}{8}.
\frac{1}{9}+\frac{\sqrt{1}}{\sqrt{8}}-\frac{11}{18}
Rewrite the square root of the division \sqrt{\frac{1}{8}} as the division of square roots \frac{\sqrt{1}}{\sqrt{8}}.
\frac{1}{9}+\frac{1}{\sqrt{8}}-\frac{11}{18}
Calculate the square root of 1 and get 1.
\frac{1}{9}+\frac{1}{2\sqrt{2}}-\frac{11}{18}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\frac{1}{9}+\frac{\sqrt{2}}{2\left(\sqrt{2}\right)^{2}}-\frac{11}{18}
Rationalize the denominator of \frac{1}{2\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{1}{9}+\frac{\sqrt{2}}{2\times 2}-\frac{11}{18}
The square of \sqrt{2} is 2.
\frac{1}{9}+\frac{\sqrt{2}}{4}-\frac{11}{18}
Multiply 2 and 2 to get 4.
-\frac{1}{2}+\frac{\sqrt{2}}{4}
Subtract \frac{11}{18} from \frac{1}{9} to get -\frac{1}{2}.
-\frac{2}{4}+\frac{\sqrt{2}}{4}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 2 and 4 is 4. Multiply -\frac{1}{2} times \frac{2}{2}.
\frac{-2+\sqrt{2}}{4}
Since -\frac{2}{4} and \frac{\sqrt{2}}{4} have the same denominator, add them by adding their numerators.