Solve (1-1/2)^2+(-1+1/2)^3=

$$( 1 - \frac { 1 } { 2 } ) ^ { 2 } + ( - 1 + \frac { 1 } { 2 } ) ^ { 3 } =$$

Evaluate

$$\frac{1}{8}=0.125$$

Solution Steps

Subtract \frac{1}{2} from 1 to get \frac{1}{2}.

$$\left(\frac{1}{2}\right)^{2}+\left(-1+\frac{1}{2}\right)^{3}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{4}+\left(-1+\frac{1}{2}\right)^{3}$$

Add -1 and \frac{1}{2} to get -\frac{1}{2}.

$$\frac{1}{4}+\left(-\frac{1}{2}\right)^{3}$$

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$\frac{1}{4}-\frac{1}{8}$$

Subtract \frac{1}{8} from \frac{1}{4} to get \frac{1}{8}.

$$\frac{1}{8}$$

Factor

$$\frac{1}{2 ^ {3}} = 0.125$$