Solve (1)(x^{3}y^2)^2+(-xy)^3*x^3y

$$( 1 ) ( x ^ { 3 } y ^ { 2 } ) ^ { 2 } + ( - x y ) ^ { 3 } \cdot x ^ { 3 } y$$

Evaluate

$$0$$

Solution Steps

Expand \left(x^{3}y^{2}\right)^{2}.

$$1\left(x^{3}\right)^{2}\left(y^{2}\right)^{2}+\left(\left(-x\right)y\right)^{3}x^{3}y$$

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$1x^{6}\left(y^{2}\right)^{2}+\left(\left(-x\right)y\right)^{3}x^{3}y$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$1x^{6}y^{4}+\left(\left(-x\right)y\right)^{3}x^{3}y$$

Expand \left(\left(-x\right)y\right)^{3}.

$$1x^{6}y^{4}+\left(-x\right)^{3}y^{3}x^{3}y$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$1x^{6}y^{4}+\left(-x\right)^{3}y^{4}x^{3}$$

Expand \left(-x\right)^{3}.

$$1x^{6}y^{4}+\left(-1\right)^{3}x^{3}y^{4}x^{3}$$

Calculate -1 to the power of 3 and get -1.

$$1x^{6}y^{4}-x^{3}y^{4}x^{3}$$

To multiply powers of the same base, add their exponents. Add 3 and 3 to get 6.

$$1x^{6}y^{4}-x^{6}y^{4}$$

Combine 1x^{6}y^{4} and -x^{6}y^{4} to get 0.

$$0$$

Factor

$$0$$