Solve (1)(-3a-2b)(3a-2b)

$$( 1 ) ( - 3 a - 2 b ) ( 3 a - 2 b )$$

Evaluate

$$4b^{2}-9a^{2}$$

Solution Steps

Use the distributive property to multiply 1 by -3a-2b.

$$\left(-3a-2b\right)\left(3a-2b\right)$$

Apply the distributive property by multiplying each term of -3a-2b by each term of 3a-2b.

$$-9a^{2}+6ab-6ba+4b^{2}$$

Combine 6ab and -6ba to get 0.

$$-9a^{2}+4b^{2}$$

Expand

$$4b^{2}-9a^{2}$$

Solution Steps

Use the distributive property to multiply 1 by -3a-2b.

$$\left(-3a-2b\right)\left(3a-2b\right)$$

Apply the distributive property by multiplying each term of -3a-2b by each term of 3a-2b.

$$-9a^{2}+6ab-6ba+4b^{2}$$

Combine 6ab and -6ba to get 0.

$$-9a^{2}+4b^{2}$$