Solve (1)7/9div11/5+5/11*2/9

$$( 1 ) \frac { 7 } { 9 } \div \frac { 11 } { 5 } + \frac { 5 } { 11 } \times \frac { 2 } { 9 }$$

Evaluate

$$\frac{5}{11}\approx 0.454545455$$

Solution Steps

Multiply 1 and \frac{7}{9} to get \frac{7}{9}.

$$\frac{\frac{7}{9}}{\frac{11}{5}}+\frac{5}{11}\times \frac{2}{9}$$

Divide \frac{7}{9} by \frac{11}{5} by multiplying \frac{7}{9} by the reciprocal of \frac{11}{5}.

$$\frac{7}{9}\times \frac{5}{11}+\frac{5}{11}\times \frac{2}{9}$$

Multiply \frac{7}{9} times \frac{5}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 5}{9\times 11}+\frac{5}{11}\times \frac{2}{9}$$

Do the multiplications in the fraction \frac{7\times 5}{9\times 11}.

$$\frac{35}{99}+\frac{5}{11}\times \frac{2}{9}$$

Multiply \frac{5}{11} times \frac{2}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{35}{99}+\frac{5\times 2}{11\times 9}$$

Do the multiplications in the fraction \frac{5\times 2}{11\times 9}.

$$\frac{35}{99}+\frac{10}{99}$$

Since \frac{35}{99} and \frac{10}{99} have the same denominator, add them by adding their numerators.

$$\frac{35+10}{99}$$

Add 35 and 10 to get 45.

$$\frac{45}{99}$$

Reduce the fraction \frac{45}{99} to lowest terms by extracting and canceling out 9.

$$\frac{5}{11}$$

Factor

$$\frac{5}{11} = 0.45454545454545453$$