Solve (13/4+24/5)*30

$$( 1 \frac { 3 } { 4 } + 2 \frac { 4 } { 5 } ) \cdot 30$$

Evaluate

$$\frac{273}{2}=136.5$$

Solution Steps

Multiply 1 and 4 to get 4.

$$\left(\frac{4+3}{4}+\frac{2\times 5+4}{5}\right)\times 30$$

Add 4 and 3 to get 7.

$$\left(\frac{7}{4}+\frac{2\times 5+4}{5}\right)\times 30$$

Multiply 2 and 5 to get 10.

$$\left(\frac{7}{4}+\frac{10+4}{5}\right)\times 30$$

Add 10 and 4 to get 14.

$$\left(\frac{7}{4}+\frac{14}{5}\right)\times 30$$

Least common multiple of 4 and 5 is 20. Convert \frac{7}{4} and \frac{14}{5} to fractions with denominator 20.

$$\left(\frac{35}{20}+\frac{56}{20}\right)\times 30$$

Since \frac{35}{20} and \frac{56}{20} have the same denominator, add them by adding their numerators.

$$\frac{35+56}{20}\times 30$$

Add 35 and 56 to get 91.

$$\frac{91}{20}\times 30$$

Express \frac{91}{20}\times 30 as a single fraction.

$$\frac{91\times 30}{20}$$

Multiply 91 and 30 to get 2730.

$$\frac{2730}{20}$$

Reduce the fraction \frac{2730}{20} to lowest terms by extracting and canceling out 10.

$$\frac{273}{2}$$

Factor

$$\frac{3 \cdot 7 \cdot 13}{2} = 136\frac{1}{2} = 136.5$$