Solve (11/9)div(4-21/3)

$$( 1 \frac { 1 } { 9 } ) \div ( 4 - 2 \frac { 1 } { 3 } )$$

Evaluate

$$\frac{2}{3}\approx 0.666666667$$

Solution Steps

Multiply 1 and 9 to get 9.

$$\frac{\frac{9+1}{9}}{4-\frac{2\times 3+1}{3}}$$

Add 9 and 1 to get 10.

$$\frac{\frac{10}{9}}{4-\frac{2\times 3+1}{3}}$$

Multiply 2 and 3 to get 6.

$$\frac{\frac{10}{9}}{4-\frac{6+1}{3}}$$

Add 6 and 1 to get 7.

$$\frac{\frac{10}{9}}{4-\frac{7}{3}}$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{\frac{10}{9}}{\frac{12}{3}-\frac{7}{3}}$$

Since \frac{12}{3} and \frac{7}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{10}{9}}{\frac{12-7}{3}}$$

Subtract 7 from 12 to get 5.

$$\frac{\frac{10}{9}}{\frac{5}{3}}$$

Divide \frac{10}{9} by \frac{5}{3} by multiplying \frac{10}{9} by the reciprocal of \frac{5}{3}.

$$\frac{10}{9}\times \frac{3}{5}$$

Multiply \frac{10}{9} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{10\times 3}{9\times 5}$$

Do the multiplications in the fraction \frac{10\times 3}{9\times 5}.

$$\frac{30}{45}$$

Reduce the fraction \frac{30}{45} to lowest terms by extracting and canceling out 15.

$$\frac{2}{3}$$

Factor

$$\frac{2}{3} = 0.6666666666666666$$