Solve (11/8-7/8)div(3/4-1/2)

$$( 1 \frac { 1 } { 8 } - \frac { 7 } { 8 } ) \div ( \frac { 3 } { 4 } - \frac { 1 } { 2 } )$$

Evaluate

$$1$$

Solution Steps

Multiply 1 and 8 to get 8.

$$\frac{\frac{8+1}{8}-\frac{7}{8}}{\frac{3}{4}-\frac{1}{2}}$$

Add 8 and 1 to get 9.

$$\frac{\frac{9}{8}-\frac{7}{8}}{\frac{3}{4}-\frac{1}{2}}$$

Since \frac{9}{8} and \frac{7}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{9-7}{8}}{\frac{3}{4}-\frac{1}{2}}$$

Subtract 7 from 9 to get 2.

$$\frac{\frac{2}{8}}{\frac{3}{4}-\frac{1}{2}}$$

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{1}{4}}{\frac{3}{4}-\frac{1}{2}}$$

Least common multiple of 4 and 2 is 4. Convert \frac{3}{4} and \frac{1}{2} to fractions with denominator 4.

$$\frac{\frac{1}{4}}{\frac{3}{4}-\frac{2}{4}}$$

Since \frac{3}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{1}{4}}{\frac{3-2}{4}}$$

Subtract 2 from 3 to get 1.

$$\frac{\frac{1}{4}}{\frac{1}{4}}$$

Divide \frac{1}{4} by \frac{1}{4} to get 1.

$$1$$

Factor

$$1$$