Solve (1/23/2:29/6-36,75)*60=

$$( 1 / 2 \frac { 3 } { 2 } : \frac { 29 } { 6 } - 36,75 ) \cdot 60 =$$

Evaluate

$$-\frac{63675}{29}\approx -2195,689655172$$

Solution Steps

Multiply \frac{1}{2} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\left(\frac{\frac{1\times 3}{2\times 2}}{\frac{29}{6}}-36,75\right)\times 60$$

Do the multiplications in the fraction \frac{1\times 3}{2\times 2}.

$$\left(\frac{\frac{3}{4}}{\frac{29}{6}}-36,75\right)\times 60$$

Divide \frac{3}{4} by \frac{29}{6} by multiplying \frac{3}{4} by the reciprocal of \frac{29}{6}.

$$\left(\frac{3}{4}\times \frac{6}{29}-36,75\right)\times 60$$

Multiply \frac{3}{4} times \frac{6}{29} by multiplying numerator times numerator and denominator times denominator.

$$\left(\frac{3\times 6}{4\times 29}-36,75\right)\times 60$$

Do the multiplications in the fraction \frac{3\times 6}{4\times 29}.

$$\left(\frac{18}{116}-36,75\right)\times 60$$

Reduce the fraction \frac{18}{116} to lowest terms by extracting and canceling out 2.

$$\left(\frac{9}{58}-36,75\right)\times 60$$

Convert decimal number 36,75 to fraction \frac{3675}{100}. Reduce the fraction \frac{3675}{100} to lowest terms by extracting and canceling out 25.

$$\left(\frac{9}{58}-\frac{147}{4}\right)\times 60$$

Least common multiple of 58 and 4 is 116. Convert \frac{9}{58} and \frac{147}{4} to fractions with denominator 116.

$$\left(\frac{18}{116}-\frac{4263}{116}\right)\times 60$$

Since \frac{18}{116} and \frac{4263}{116} have the same denominator, subtract them by subtracting their numerators.

$$\frac{18-4263}{116}\times 60$$

Subtract 4263 from 18 to get -4245.

$$-\frac{4245}{116}\times 60$$

Express -\frac{4245}{116}\times 60 as a single fraction.

$$\frac{-4245\times 60}{116}$$

Multiply -4245 and 60 to get -254700.

$$\frac{-254700}{116}$$

Reduce the fraction \frac{-254700}{116} to lowest terms by extracting and canceling out 4.

$$-\frac{63675}{29}$$

Factor

$$-\frac{63675}{29} = -2195\frac{20}{29} = -2195.689655172414$$