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x=\frac{2i}{1+i}
Divide both sides by 1+i.
x=\frac{2i\left(1-i\right)}{\left(1+i\right)\left(1-i\right)}
Multiply both numerator and denominator of \frac{2i}{1+i} by the complex conjugate of the denominator, 1-i.
x=\frac{2i\left(1-i\right)}{1^{2}-i^{2}}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
x=\frac{2i\left(1-i\right)}{2}
By definition, i^{2} is -1. Calculate the denominator.
x=\frac{2i\times 1+2\left(-1\right)i^{2}}{2}
Multiply 2i times 1-i.
x=\frac{2i\times 1+2\left(-1\right)\left(-1\right)}{2}
By definition, i^{2} is -1.
x=\frac{2+2i}{2}
Do the multiplications in 2i\times 1+2\left(-1\right)\left(-1\right). Reorder the terms.
x=1+i
Divide 2+2i by 2 to get 1+i.