Solve (1+2*3)^{2}-[2^{3}*(12-3^{2})+2-2^{2}*(3^2-2^3)^4-2^4]=

$$( 1 + 2 \times 3 ) ^ { 2 } - [ 2 ^ { 3 } \times ( 12 - 3 ^ { 2 } ) + 2 - 2 ^ { 2 } \times ( 3 ^ { 2 } - 2 ^ { 3 } ) ^ { 4 } - 2 ^ { 4 } ] =$$

Evaluate

$$43$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\left(1+6\right)^{2}-\left(2^{3}\left(12-3^{2}\right)+2-2^{2}\left(3^{2}-2^{3}\right)^{4}-2^{4}\right)$$

Add 1 and 6 to get 7.

$$7^{2}-\left(2^{3}\left(12-3^{2}\right)+2-2^{2}\left(3^{2}-2^{3}\right)^{4}-2^{4}\right)$$

Calculate 7 to the power of 2 and get 49.

$$49-\left(2^{3}\left(12-3^{2}\right)+2-2^{2}\left(3^{2}-2^{3}\right)^{4}-2^{4}\right)$$

Calculate 2 to the power of 3 and get 8.

$$49-\left(8\left(12-3^{2}\right)+2-2^{2}\left(3^{2}-2^{3}\right)^{4}-2^{4}\right)$$

Calculate 3 to the power of 2 and get 9.

$$49-\left(8\left(12-9\right)+2-2^{2}\left(3^{2}-2^{3}\right)^{4}-2^{4}\right)$$

Subtract 9 from 12 to get 3.

$$49-\left(8\times 3+2-2^{2}\left(3^{2}-2^{3}\right)^{4}-2^{4}\right)$$

Multiply 8 and 3 to get 24.

$$49-\left(24+2-2^{2}\left(3^{2}-2^{3}\right)^{4}-2^{4}\right)$$

Add 24 and 2 to get 26.

$$49-\left(26-2^{2}\left(3^{2}-2^{3}\right)^{4}-2^{4}\right)$$

Calculate 2 to the power of 2 and get 4.

$$49-\left(26-4\left(3^{2}-2^{3}\right)^{4}-2^{4}\right)$$

Calculate 3 to the power of 2 and get 9.

$$49-\left(26-4\left(9-2^{3}\right)^{4}-2^{4}\right)$$

Calculate 2 to the power of 3 and get 8.

$$49-\left(26-4\left(9-8\right)^{4}-2^{4}\right)$$

Subtract 8 from 9 to get 1.

$$49-\left(26-4\times 1^{4}-2^{4}\right)$$

Calculate 1 to the power of 4 and get 1.

$$49-\left(26-4\times 1-2^{4}\right)$$

Multiply 4 and 1 to get 4.

$$49-\left(26-4-2^{4}\right)$$

Subtract 4 from 26 to get 22.

$$49-\left(22-2^{4}\right)$$

Calculate 2 to the power of 4 and get 16.

$$49-\left(22-16\right)$$

Subtract 16 from 22 to get 6.

$$49-6$$

Subtract 6 from 49 to get 43.

$$43$$

Factor

$$43$$