Solve for x
x=0
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\left(\frac{5}{5}+\frac{4}{5}\right)x=x
Convert 1 to fraction \frac{5}{5}.
\frac{5+4}{5}x=x
Since \frac{5}{5} and \frac{4}{5} have the same denominator, add them by adding their numerators.
\frac{9}{5}x=x
Add 5 and 4 to get 9.
\frac{9}{5}x-x=0
Subtract x from both sides.
\frac{4}{5}x=0
Combine \frac{9}{5}x and -x to get \frac{4}{5}x.
x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since \frac{4}{5} is not equal to 0, x must be equal to 0.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}