Solve (1+1/8)div(1/8-1)*3/8=

$$( 1 + \frac { 1 } { 8 } ) \div ( \frac { 1 } { 8 } - 1 ) \times \frac { 3 } { 8 } =$$

Evaluate

$$-\frac{27}{56}\approx -0.482142857$$

Solution Steps

Convert 1 to fraction \frac{8}{8}.

$$\frac{\frac{8}{8}+\frac{1}{8}}{\frac{1}{8}-1}\times \frac{3}{8}$$

Since \frac{8}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$\frac{\frac{8+1}{8}}{\frac{1}{8}-1}\times \frac{3}{8}$$

Add 8 and 1 to get 9.

$$\frac{\frac{9}{8}}{\frac{1}{8}-1}\times \frac{3}{8}$$

Convert 1 to fraction \frac{8}{8}.

$$\frac{\frac{9}{8}}{\frac{1}{8}-\frac{8}{8}}\times \frac{3}{8}$$

Since \frac{1}{8} and \frac{8}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{9}{8}}{\frac{1-8}{8}}\times \frac{3}{8}$$

Subtract 8 from 1 to get -7.

$$\frac{\frac{9}{8}}{-\frac{7}{8}}\times \frac{3}{8}$$

Divide \frac{9}{8} by -\frac{7}{8} by multiplying \frac{9}{8} by the reciprocal of -\frac{7}{8}.

$$\frac{9}{8}\left(-\frac{8}{7}\right)\times \frac{3}{8}$$

Multiply \frac{9}{8} times -\frac{8}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\left(-8\right)}{8\times 7}\times \frac{3}{8}$$

Do the multiplications in the fraction \frac{9\left(-8\right)}{8\times 7}.

$$\frac{-72}{56}\times \frac{3}{8}$$

Reduce the fraction \frac{-72}{56} to lowest terms by extracting and canceling out 8.

$$-\frac{9}{7}\times \frac{3}{8}$$

Multiply -\frac{9}{7} times \frac{3}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-9\times 3}{7\times 8}$$

Do the multiplications in the fraction \frac{-9\times 3}{7\times 8}.

$$\frac{-27}{56}$$

Fraction \frac{-27}{56} can be rewritten as -\frac{27}{56} by extracting the negative sign.

$$-\frac{27}{56}$$

Factor

$$-\frac{27}{56} = -0.48214285714285715$$