Solve for x (complex solution)
\left\{\begin{matrix}x=\frac{5y}{\Phi +5}\text{, }&\Phi \neq -5\\x\in \mathrm{C}\text{, }&y=0\text{ and }\Phi =-5\end{matrix}\right.
Solve for x
\left\{\begin{matrix}x=\frac{5y}{\Phi +5}\text{, }&\Phi \neq -5\\x\in \mathrm{R}\text{, }&y=0\text{ and }\Phi =-5\end{matrix}\right.
Solve for y
y=\frac{x\left(\Phi +5\right)}{5}
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\left(\frac{\Phi }{5}+1\right)x=y
The equation is in standard form.
\frac{\left(\frac{\Phi }{5}+1\right)x}{\frac{\Phi }{5}+1}=\frac{y}{\frac{\Phi }{5}+1}
Divide both sides by 1+\frac{1}{5}\Phi .
x=\frac{y}{\frac{\Phi }{5}+1}
Dividing by 1+\frac{1}{5}\Phi undoes the multiplication by 1+\frac{1}{5}\Phi .
x=\frac{5y}{\Phi +5}
Divide y by 1+\frac{1}{5}\Phi .
\left(\frac{\Phi }{5}+1\right)x=y
The equation is in standard form.
\frac{\left(\frac{\Phi }{5}+1\right)x}{\frac{\Phi }{5}+1}=\frac{y}{\frac{\Phi }{5}+1}
Divide both sides by 1+\frac{1}{5}\Phi .
x=\frac{y}{\frac{\Phi }{5}+1}
Dividing by 1+\frac{1}{5}\Phi undoes the multiplication by 1+\frac{1}{5}\Phi .
x=\frac{5y}{\Phi +5}
Divide y by 1+\frac{1}{5}\Phi .
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