Solve (0,001)^2+2*0,001*0,999+(0,999)^2

$$( 0,001 ) ^ { 2 } + 2 \times 0,001 \times 0,999 + ( 0,999 ) ^ { 2 }$$

Evaluate

$$1$$

Solution Steps

Calculate 0,001 to the power of 2 and get 0,000001.

$$0,000001+2\times 0,001\times 0,999+0,999^{2}$$

Multiply 2 and 0,001 to get 0,002.

$$0,000001+0,002\times 0,999+0,999^{2}$$

Multiply 0,002 and 0,999 to get 0,001998.

$$0,000001+0,001998+0,999^{2}$$

Add 0,000001 and 0,001998 to get 0,001999.

$$0,001999+0,999^{2}$$

Calculate 0,999 to the power of 2 and get 0,998001.

$$0,001999+0,998001$$

Add 0,001999 and 0,998001 to get 1.

$$1$$

Factor

$$1$$