Solve (-94/5)+(-401/2)+3.8

$$( - 9 \frac { 4 } { 5 } ) + ( - 40 \frac { 1 } { 2 } ) + 3.8$$

Evaluate

$$-46.5$$

Solution Steps

Multiply 9 and 5 to get 45.

$$-\frac{45+4}{5}-\frac{40\times 2+1}{2}+3.8$$

Add 45 and 4 to get 49.

$$-\frac{49}{5}-\frac{40\times 2+1}{2}+3.8$$

Multiply 40 and 2 to get 80.

$$-\frac{49}{5}-\frac{80+1}{2}+3.8$$

Add 80 and 1 to get 81.

$$-\frac{49}{5}-\frac{81}{2}+3.8$$

Least common multiple of 5 and 2 is 10. Convert -\frac{49}{5} and \frac{81}{2} to fractions with denominator 10.

$$-\frac{98}{10}-\frac{405}{10}+3.8$$

Since -\frac{98}{10} and \frac{405}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-98-405}{10}+3.8$$

Subtract 405 from -98 to get -503.

$$-\frac{503}{10}+3.8$$

Convert decimal number 3.8 to fraction \frac{38}{10}. Reduce the fraction \frac{38}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{503}{10}+\frac{19}{5}$$

Least common multiple of 10 and 5 is 10. Convert -\frac{503}{10} and \frac{19}{5} to fractions with denominator 10.

$$-\frac{503}{10}+\frac{38}{10}$$

Since -\frac{503}{10} and \frac{38}{10} have the same denominator, add them by adding their numerators.

$$\frac{-503+38}{10}$$

Add -503 and 38 to get -465.

$$\frac{-465}{10}$$

Reduce the fraction \frac{-465}{10} to lowest terms by extracting and canceling out 5.

$$-\frac{93}{2}$$

Factor

$$-46.5$$