Solve (-5)x(+8)^2+6-5div(2)^2

$$( - 5 ) x ( + 8 ) ^ { 2 } + 6 - 5 \div ( 2 ) ^ { 2 }$$

Evaluate

$$\frac{19}{4}-320x$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$-5x\times 64+6-\frac{5}{2^{2}}$$

Multiply -5 and 64 to get -320.

$$-320x+6-\frac{5}{2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$-320x+6-\frac{5}{4}$$

Convert 6 to fraction \frac{24}{4}.

$$-320x+\frac{24}{4}-\frac{5}{4}$$

Since \frac{24}{4} and \frac{5}{4} have the same denominator, subtract them by subtracting their numerators.

$$-320x+\frac{24-5}{4}$$

Subtract 5 from 24 to get 19.

$$-320x+\frac{19}{4}$$

Factor

$$\frac{19-1280x}{4}$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$factor(-5x\times 64+6-\frac{5}{2^{2}})$$

Multiply -5 and 64 to get -320.

$$factor(-320x+6-\frac{5}{2^{2}})$$

Calculate 2 to the power of 2 and get 4.

$$factor(-320x+6-\frac{5}{4})$$

Convert 6 to fraction \frac{24}{4}.

$$factor(-320x+\frac{24}{4}-\frac{5}{4})$$

Since \frac{24}{4} and \frac{5}{4} have the same denominator, subtract them by subtracting their numerators.

$$factor(-320x+\frac{24-5}{4})$$

Subtract 5 from 24 to get 19.

$$factor(-320x+\frac{19}{4})$$

Factor out \frac{1}{4}.

$$\frac{-1280x+19}{4}$$