Solve (-51/16)*(-91/3)div(-3/2)

$$( - 5 \frac { 1 } { 16 } ) \times ( - 9 \frac { 1 } { 3 } ) \div ( - \frac { 3 } { 2 } )$$

Evaluate

$$-\frac{63}{2}=-31.5$$

Solution Steps

Multiply 5 and 16 to get 80.

$$\frac{\left(-\frac{80+1}{16}\right)\left(-\frac{9\times 3+1}{3}\right)}{-\frac{3}{2}}$$

Add 80 and 1 to get 81.

$$\frac{-\frac{81}{16}\left(-\frac{9\times 3+1}{3}\right)}{-\frac{3}{2}}$$

Multiply 9 and 3 to get 27.

$$\frac{-\frac{81}{16}\left(-\frac{27+1}{3}\right)}{-\frac{3}{2}}$$

Add 27 and 1 to get 28.

$$\frac{-\frac{81}{16}\left(-\frac{28}{3}\right)}{-\frac{3}{2}}$$

Multiply -\frac{81}{16} times -\frac{28}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{-81\left(-28\right)}{16\times 3}}{-\frac{3}{2}}$$

Do the multiplications in the fraction \frac{-81\left(-28\right)}{16\times 3}.

$$\frac{\frac{2268}{48}}{-\frac{3}{2}}$$

Reduce the fraction \frac{2268}{48} to lowest terms by extracting and canceling out 12.

$$\frac{\frac{189}{4}}{-\frac{3}{2}}$$

Divide \frac{189}{4} by -\frac{3}{2} by multiplying \frac{189}{4} by the reciprocal of -\frac{3}{2}.

$$\frac{189}{4}\left(-\frac{2}{3}\right)$$

Multiply \frac{189}{4} times -\frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{189\left(-2\right)}{4\times 3}$$

Do the multiplications in the fraction \frac{189\left(-2\right)}{4\times 3}.

$$\frac{-378}{12}$$

Reduce the fraction \frac{-378}{12} to lowest terms by extracting and canceling out 6.

$$-\frac{63}{2}$$

Factor

$$-\frac{63}{2} = -31\frac{1}{2} = -31.5$$