Solve (-42/7+33/14)*14

$$( - 4 \frac { 2 } { 7 } + 3 \frac { 3 } { 14 } ) \cdot 14$$

Evaluate

$$-15$$

Solution Steps

Multiply 4 and 7 to get 28.

$$\left(-\frac{28+2}{7}+\frac{3\times 14+3}{14}\right)\times 14$$

Add 28 and 2 to get 30.

$$\left(-\frac{30}{7}+\frac{3\times 14+3}{14}\right)\times 14$$

Multiply 3 and 14 to get 42.

$$\left(-\frac{30}{7}+\frac{42+3}{14}\right)\times 14$$

Add 42 and 3 to get 45.

$$\left(-\frac{30}{7}+\frac{45}{14}\right)\times 14$$

Least common multiple of 7 and 14 is 14. Convert -\frac{30}{7} and \frac{45}{14} to fractions with denominator 14.

$$\left(-\frac{60}{14}+\frac{45}{14}\right)\times 14$$

Since -\frac{60}{14} and \frac{45}{14} have the same denominator, add them by adding their numerators.

$$\frac{-60+45}{14}\times 14$$

Add -60 and 45 to get -15.

$$-\frac{15}{14}\times 14$$

Cancel out 14 and 14.

$$-15$$

Factor

$$-15$$