Solve (-4+5)div(-1)+3-21div(-7)div3[-11(-2)-19]

$$( - 4 + 5 ) \div ( - 1 ) + 3 - 21 \div ( - 7 ) \div 3 [ - 11 ( - 2 ) - 19 ]$$

Evaluate

$$5$$

Solution Steps

Add -4 and 5 to get 1.

$$\frac{1}{-1}+3-\frac{\frac{21}{-7}}{3}\left(-11\left(-2\right)-19\right)$$

Divide 1 by -1 to get -1.

$$-1+3-\frac{\frac{21}{-7}}{3}\left(-11\left(-2\right)-19\right)$$

Add -1 and 3 to get 2.

$$2-\frac{\frac{21}{-7}}{3}\left(-11\left(-2\right)-19\right)$$

Express \frac{\frac{21}{-7}}{3} as a single fraction.

$$2-\frac{21}{-7\times 3}\left(-11\left(-2\right)-19\right)$$

Multiply -7 and 3 to get -21.

$$2-\frac{21}{-21}\left(-11\left(-2\right)-19\right)$$

Divide 21 by -21 to get -1.

$$2-\left(-\left(-11\left(-2\right)-19\right)\right)$$

Multiply -11 and -2 to get 22.

$$2-\left(-\left(22-19\right)\right)$$

Subtract 19 from 22 to get 3.

$$2-\left(-3\right)$$

The opposite of -3 is 3.

$$2+3$$

Add 2 and 3 to get 5.

$$5$$

Factor

$$5$$