Solve (-3)(1/2)-(2/3)^2(-3)

$$( - 3 ) ( \frac { 1 } { 2 } ) - ( \frac { 2 } { 3 } ) ^ { 2 } ( - 3 )$$

Evaluate

$$-\frac{1}{6}\approx -0.166666667$$

Solution Steps

Multiply -3 and \frac{1}{2} to get \frac{-3}{2}.

$$\frac{-3}{2}-\left(\frac{2}{3}\right)^{2}\left(-3\right)$$

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$-\frac{3}{2}-\left(\frac{2}{3}\right)^{2}\left(-3\right)$$

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$-\frac{3}{2}-\frac{4}{9}\left(-3\right)$$

Express \frac{4}{9}\left(-3\right) as a single fraction.

$$-\frac{3}{2}-\frac{4\left(-3\right)}{9}$$

Multiply 4 and -3 to get -12.

$$-\frac{3}{2}-\frac{-12}{9}$$

Reduce the fraction \frac{-12}{9} to lowest terms by extracting and canceling out 3.

$$-\frac{3}{2}-\left(-\frac{4}{3}\right)$$

The opposite of -\frac{4}{3} is \frac{4}{3}.

$$-\frac{3}{2}+\frac{4}{3}$$

Least common multiple of 2 and 3 is 6. Convert -\frac{3}{2} and \frac{4}{3} to fractions with denominator 6.

$$-\frac{9}{6}+\frac{8}{6}$$

Since -\frac{9}{6} and \frac{8}{6} have the same denominator, add them by adding their numerators.

$$\frac{-9+8}{6}$$

Add -9 and 8 to get -1.

$$-\frac{1}{6}$$

Factor

$$-\frac{1}{6} = -0.16666666666666666$$