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\left(-2\right)^{2}x^{2}=\left(x+9\right)x
Expand \left(-2x\right)^{2}.
4x^{2}=\left(x+9\right)x
Calculate -2 to the power of 2 and get 4.
4x^{2}=x^{2}+9x
Use the distributive property to multiply x+9 by x.
4x^{2}-x^{2}=9x
Subtract x^{2} from both sides.
3x^{2}=9x
Combine 4x^{2} and -x^{2} to get 3x^{2}.
3x^{2}-9x=0
Subtract 9x from both sides.
x\left(3x-9\right)=0
Factor out x.
x=0 x=3
To find equation solutions, solve x=0 and 3x-9=0.
\left(-2\right)^{2}x^{2}=\left(x+9\right)x
Expand \left(-2x\right)^{2}.
4x^{2}=\left(x+9\right)x
Calculate -2 to the power of 2 and get 4.
4x^{2}=x^{2}+9x
Use the distributive property to multiply x+9 by x.
4x^{2}-x^{2}=9x
Subtract x^{2} from both sides.
3x^{2}=9x
Combine 4x^{2} and -x^{2} to get 3x^{2}.
3x^{2}-9x=0
Subtract 9x from both sides.
x=\frac{-\left(-9\right)±\sqrt{\left(-9\right)^{2}}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, -9 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-9\right)±9}{2\times 3}
Take the square root of \left(-9\right)^{2}.
x=\frac{9±9}{2\times 3}
The opposite of -9 is 9.
x=\frac{9±9}{6}
Multiply 2 times 3.
x=\frac{18}{6}
Now solve the equation x=\frac{9±9}{6} when ± is plus. Add 9 to 9.
x=3
Divide 18 by 6.
x=\frac{0}{6}
Now solve the equation x=\frac{9±9}{6} when ± is minus. Subtract 9 from 9.
x=0
Divide 0 by 6.
x=3 x=0
The equation is now solved.
\left(-2\right)^{2}x^{2}=\left(x+9\right)x
Expand \left(-2x\right)^{2}.
4x^{2}=\left(x+9\right)x
Calculate -2 to the power of 2 and get 4.
4x^{2}=x^{2}+9x
Use the distributive property to multiply x+9 by x.
4x^{2}-x^{2}=9x
Subtract x^{2} from both sides.
3x^{2}=9x
Combine 4x^{2} and -x^{2} to get 3x^{2}.
3x^{2}-9x=0
Subtract 9x from both sides.
\frac{3x^{2}-9x}{3}=\frac{0}{3}
Divide both sides by 3.
x^{2}+\left(-\frac{9}{3}\right)x=\frac{0}{3}
Dividing by 3 undoes the multiplication by 3.
x^{2}-3x=\frac{0}{3}
Divide -9 by 3.
x^{2}-3x=0
Divide 0 by 3.
x^{2}-3x+\left(-\frac{3}{2}\right)^{2}=\left(-\frac{3}{2}\right)^{2}
Divide -3, the coefficient of the x term, by 2 to get -\frac{3}{2}. Then add the square of -\frac{3}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-3x+\frac{9}{4}=\frac{9}{4}
Square -\frac{3}{2} by squaring both the numerator and the denominator of the fraction.
\left(x-\frac{3}{2}\right)^{2}=\frac{9}{4}
Factor x^{2}-3x+\frac{9}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{3}{2}\right)^{2}}=\sqrt{\frac{9}{4}}
Take the square root of both sides of the equation.
x-\frac{3}{2}=\frac{3}{2} x-\frac{3}{2}=-\frac{3}{2}
Simplify.
x=3 x=0
Add \frac{3}{2} to both sides of the equation.