Solve (-2ab^2)*(ma^2b^2)

$$( - 2 a b ^ { 2 } ) \cdot ( m a ^ { 2 } b ^ { 2 } )$$

Evaluate

$$-2ma^{3}b^{4}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$\left(-2\right)^{1}a^{1}b^{2}m^{1}a^{2}b^{2}$$

Use the Commutative Property of Multiplication.

$$\left(-2\right)^{1}m^{1}a^{1}a^{2}b^{2}b^{2}$$

To multiply powers of the same base, add their exponents.

$$\left(-2\right)^{1}m^{1}a^{1+2}b^{2+2}$$

Add the exponents 1 and 2.

$$\left(-2\right)^{1}m^{1}a^{3}b^{2+2}$$

Add the exponents 2 and 2.

$$\left(-2\right)^{1}m^{1}a^{3}b^{4}$$

Multiply -2 times m.

$$\left(-2m\right)a^{3}b^{4}$$

Differentiate w.r.t. m

$$-2a^{3}b^{4}$$