Solve (-2a^2b)*(-a^2)*1/4bc

$$( - 2 a ^ { 2 } b ) \cdot ( - a ^ { 2 } ) \cdot \frac { 1 } { 4 } b c$$

Evaluate

$$\frac{cb^{2}a^{4}}{2}$$

Solution Steps

Multiply b and b to get b^{2}.

$$-2a^{2}b^{2}\left(-a^{2}\right)\times \frac{1}{4}c$$

Multiply -2 and \frac{1}{4} to get -\frac{1}{2}.

$$-\frac{1}{2}a^{2}b^{2}\left(-a^{2}\right)c$$

Multiply -\frac{1}{2} and -1 to get \frac{1}{2}.

$$\frac{1}{2}a^{2}b^{2}a^{2}c$$

To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.

$$\frac{1}{2}a^{4}b^{2}c$$

Differentiate w.r.t. c

$$\frac{b^{2}a^{4}}{2}$$