Solve (-2)ab^2x(+10)ab(-2)a

$$( - 2 ) a b ^ { 2 } x ( + 10 ) a b ( - 2 ) a$$

Evaluate

$$40x\left(ab\right)^{3}$$

Solution Steps

Multiply a and a to get a^{2}.

$$-2a^{2}b^{2}x\times 10b\left(-2\right)a$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$-2a^{3}b^{2}x\times 10b\left(-2\right)$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$-2a^{3}b^{3}x\times 10\left(-2\right)$$

Multiply -2 and 10 to get -20.

$$-20a^{3}b^{3}x\left(-2\right)$$

Multiply -20 and -2 to get 40.

$$40a^{3}b^{3}x$$

Differentiate w.r.t. x

$$40\left(ab\right)^{3}$$