Solve (-2)^3:1,6+(-3)^2:2/3

$$( - 2 ) ^ { 3 } : 1,6 + ( - 3 ) ^ { 2 } : \frac { 2 } { 3 }$$

Evaluate

$$8,5$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$\frac{-8}{1,6}+\frac{\left(-3\right)^{2}}{\frac{2}{3}}$$

Expand \frac{-8}{1,6} by multiplying both numerator and the denominator by 10.

$$\frac{-80}{16}+\frac{\left(-3\right)^{2}}{\frac{2}{3}}$$

Divide -80 by 16 to get -5.

$$-5+\frac{\left(-3\right)^{2}}{\frac{2}{3}}$$

Calculate -3 to the power of 2 and get 9.

$$-5+\frac{9}{\frac{2}{3}}$$

Divide 9 by \frac{2}{3} by multiplying 9 by the reciprocal of \frac{2}{3}.

$$-5+9\times \frac{3}{2}$$

Express 9\times \frac{3}{2} as a single fraction.

$$-5+\frac{9\times 3}{2}$$

Multiply 9 and 3 to get 27.

$$-5+\frac{27}{2}$$

Convert -5 to fraction -\frac{10}{2}.

$$-\frac{10}{2}+\frac{27}{2}$$

Since -\frac{10}{2} and \frac{27}{2} have the same denominator, add them by adding their numerators.

$$\frac{-10+27}{2}$$

Add -10 and 27 to get 17.

$$\frac{17}{2}$$

Factor

$$\frac{17}{2} = 8\frac{1}{2} = 8.5$$