Solve (-2)^3+3(4-18:6)(6-2-(-5)*2*4)

$$( - 2 ) ^ { 3 } + 3 ( 4 - 18 : 6 ) ( 6 - 2 - ( - 5 ) \cdot 2 \cdot 4 )$$

Evaluate

$$124$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+3\left(4-\frac{18}{6}\right)\left(6-2-\left(-5\times 2\times 4\right)\right)$$

Divide 18 by 6 to get 3.

$$-8+3\left(4-3\right)\left(6-2-\left(-5\times 2\times 4\right)\right)$$

Subtract 3 from 4 to get 1.

$$-8+3\times 1\left(6-2-\left(-5\times 2\times 4\right)\right)$$

Multiply 3 and 1 to get 3.

$$-8+3\left(6-2-\left(-5\times 2\times 4\right)\right)$$

Subtract 2 from 6 to get 4.

$$-8+3\left(4-\left(-5\times 2\times 4\right)\right)$$

Multiply -5 and 2 to get -10.

$$-8+3\left(4-\left(-10\times 4\right)\right)$$

Multiply -10 and 4 to get -40.

$$-8+3\left(4-\left(-40\right)\right)$$

The opposite of -40 is 40.

$$-8+3\left(4+40\right)$$

Add 4 and 40 to get 44.

$$-8+3\times 44$$

Multiply 3 and 44 to get 132.

$$-8+132$$

Add -8 and 132 to get 124.

$$124$$

Factor

$$2^{2}\times 31$$