Solve (-2)^3+(-1)^0-sqrt{25}-3^2-5^3:25

$$( - 2 ) ^ { 3 } + ( - 1 ) ^ { 0 } - \sqrt { 25 } - 3 ^ { 2 } - 5 ^ { 3 } : 25$$

Evaluate

$$-26$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+\left(-1\right)^{0}-\sqrt{25}-3^{2}-\frac{5^{3}}{25}$$

Calculate -1 to the power of 0 and get 1.

$$-8+1-\sqrt{25}-3^{2}-\frac{5^{3}}{25}$$

Add -8 and 1 to get -7.

$$-7-\sqrt{25}-3^{2}-\frac{5^{3}}{25}$$

Calculate the square root of 25 and get 5.

$$-7-5-3^{2}-\frac{5^{3}}{25}$$

Subtract 5 from -7 to get -12.

$$-12-3^{2}-\frac{5^{3}}{25}$$

Calculate 3 to the power of 2 and get 9.

$$-12-9-\frac{5^{3}}{25}$$

Subtract 9 from -12 to get -21.

$$-21-\frac{5^{3}}{25}$$

Calculate 5 to the power of 3 and get 125.

$$-21-\frac{125}{25}$$

Divide 125 by 25 to get 5.

$$-21-5$$

Subtract 5 from -21 to get -26.

$$-26$$

Factor

$$-26$$