Solve (-2)^3+(1/2)^-2*2^2-(pi-2)^0

$$( - 2 ) ^ { 3 } + ( \frac { 1 } { 2 } ) ^ { - 2 } \times 2 ^ { 2 } - ( \pi - 2 ) ^ { 0 }$$

Evaluate

$$7$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-8+\left(\frac{1}{2}\right)^{-2}\times 2^{2}-\left(\pi -2\right)^{0}$$

Calculate \frac{1}{2} to the power of -2 and get 4.

$$-8+4\times 2^{2}-\left(\pi -2\right)^{0}$$

Calculate 2 to the power of 2 and get 4.

$$-8+4\times 4-\left(\pi -2\right)^{0}$$

Multiply 4 and 4 to get 16.

$$-8+16-\left(\pi -2\right)^{0}$$

Add -8 and 16 to get 8.

$$8-\left(\pi -2\right)^{0}$$

Calculate \pi -2 to the power of 0 and get 1.

$$8-1$$

Subtract 1 from 8 to get 7.

$$7$$

Factor

$$7$$