Solve (-2)^{2}*4^{2}:(-2)^6-(-3)^3-25*1^100-(-5)^2

$$( - 2 ) ^ { 2 } \cdot 4 ^ { 2 } : ( - 2 ) ^ { 6 } - ( - 3 ) ^ { 3 } - 25 \cdot 1 ^ { 100 } - ( - 5 ) ^ { 2 }$$

Evaluate

$$-22$$

Solution Steps

Cancel out \left(-2\right)^{2} in both numerator and denominator.

$$\frac{4^{2}}{\left(-2\right)^{4}}-\left(-3\right)^{3}-25\times 1^{100}-\left(-5\right)^{2}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{16}{\left(-2\right)^{4}}-\left(-3\right)^{3}-25\times 1^{100}-\left(-5\right)^{2}$$

Calculate -2 to the power of 4 and get 16.

$$\frac{16}{16}-\left(-3\right)^{3}-25\times 1^{100}-\left(-5\right)^{2}$$

Divide 16 by 16 to get 1.

$$1-\left(-3\right)^{3}-25\times 1^{100}-\left(-5\right)^{2}$$

Calculate -3 to the power of 3 and get -27.

$$1-\left(-27\right)-25\times 1^{100}-\left(-5\right)^{2}$$

The opposite of -27 is 27.

$$1+27-25\times 1^{100}-\left(-5\right)^{2}$$

Add 1 and 27 to get 28.

$$28-25\times 1^{100}-\left(-5\right)^{2}$$

Calculate 1 to the power of 100 and get 1.

$$28-25\times 1-\left(-5\right)^{2}$$

Multiply 25 and 1 to get 25.

$$28-25-\left(-5\right)^{2}$$

Subtract 25 from 28 to get 3.

$$3-\left(-5\right)^{2}$$

Calculate -5 to the power of 2 and get 25.

$$3-25$$

Subtract 25 from 3 to get -22.

$$-22$$

Factor

$$-22$$