Solve (-2)^2+(6-(-3)*2)div4-5div5/9*(2/3)^2

$$( - 2 ) ^ { 2 } + ( 6 - ( - 3 ) \times 2 ) \div 4 - 5 \div \frac { 5 } { 9 } \times ( \frac { 2 } { 3 } ) ^ { 2 }$$

Evaluate

$$3$$

Solution Steps

Calculate -2 to the power of 2 and get 4.

$$4+\frac{6-\left(-3\times 2\right)}{4}-\frac{5}{\frac{5}{9}}\times \left(\frac{2}{3}\right)^{2}$$

Multiply -3 and 2 to get -6.

$$4+\frac{6-\left(-6\right)}{4}-\frac{5}{\frac{5}{9}}\times \left(\frac{2}{3}\right)^{2}$$

The opposite of -6 is 6.

$$4+\frac{6+6}{4}-\frac{5}{\frac{5}{9}}\times \left(\frac{2}{3}\right)^{2}$$

Add 6 and 6 to get 12.

$$4+\frac{12}{4}-\frac{5}{\frac{5}{9}}\times \left(\frac{2}{3}\right)^{2}$$

Divide 12 by 4 to get 3.

$$4+3-\frac{5}{\frac{5}{9}}\times \left(\frac{2}{3}\right)^{2}$$

Add 4 and 3 to get 7.

$$7-\frac{5}{\frac{5}{9}}\times \left(\frac{2}{3}\right)^{2}$$

Divide 5 by \frac{5}{9} by multiplying 5 by the reciprocal of \frac{5}{9}.

$$7-5\times \frac{9}{5}\times \left(\frac{2}{3}\right)^{2}$$

Cancel out 5 and 5.

$$7-9\times \left(\frac{2}{3}\right)^{2}$$

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$7-9\times \frac{4}{9}$$

Cancel out 9 and 9.

$$7-4$$

Subtract 4 from 7 to get 3.

$$3$$

Factor

$$3$$