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\left(-2\right)^{2}\left(\sqrt{2}\right)^{2}-\left(\sqrt{2}+1\right)^{2}
Expand \left(-2\sqrt{2}\right)^{2}.
4\left(\sqrt{2}\right)^{2}-\left(\sqrt{2}+1\right)^{2}
Calculate -2 to the power of 2 and get 4.
4\times 2-\left(\sqrt{2}+1\right)^{2}
The square of \sqrt{2} is 2.
8-\left(\sqrt{2}+1\right)^{2}
Multiply 4 and 2 to get 8.
8-\left(\left(\sqrt{2}\right)^{2}+2\sqrt{2}+1\right)
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{2}+1\right)^{2}.
8-\left(2+2\sqrt{2}+1\right)
The square of \sqrt{2} is 2.
8-\left(3+2\sqrt{2}\right)
Add 2 and 1 to get 3.
8-3-2\sqrt{2}
To find the opposite of 3+2\sqrt{2}, find the opposite of each term.
5-2\sqrt{2}
Subtract 3 from 8 to get 5.
\left(-2\right)^{2}\left(\sqrt{2}\right)^{2}-\left(\sqrt{2}+1\right)^{2}
Expand \left(-2\sqrt{2}\right)^{2}.
4\left(\sqrt{2}\right)^{2}-\left(\sqrt{2}+1\right)^{2}
Calculate -2 to the power of 2 and get 4.
4\times 2-\left(\sqrt{2}+1\right)^{2}
The square of \sqrt{2} is 2.
8-\left(\sqrt{2}+1\right)^{2}
Multiply 4 and 2 to get 8.
8-\left(\left(\sqrt{2}\right)^{2}+2\sqrt{2}+1\right)
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{2}+1\right)^{2}.
8-\left(2+2\sqrt{2}+1\right)
The square of \sqrt{2} is 2.
8-\left(3+2\sqrt{2}\right)
Add 2 and 1 to get 3.
8-3-2\sqrt{2}
To find the opposite of 3+2\sqrt{2}, find the opposite of each term.
5-2\sqrt{2}
Subtract 3 from 8 to get 5.