Solve (-21/3+3/4)*(-11/2)^3-2

$$( - 2 \frac { 1 } { 3 } + \frac { 3 } { 4 } ) \times ( - 1 \frac { 1 } { 2 } ) ^ { 3 } - 2$$

Evaluate

$$\frac{107}{32}=3.34375$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\left(-\frac{6+1}{3}+\frac{3}{4}\right)\left(-\frac{1\times 2+1}{2}\right)^{3}-2$$

Add 6 and 1 to get 7.

$$\left(-\frac{7}{3}+\frac{3}{4}\right)\left(-\frac{1\times 2+1}{2}\right)^{3}-2$$

Add -\frac{7}{3} and \frac{3}{4} to get -\frac{19}{12}.

$$-\frac{19}{12}\left(-\frac{2+1}{2}\right)^{3}-2$$

Add 2 and 1 to get 3.

$$-\frac{19}{12}\left(-\frac{3}{2}\right)^{3}-2$$

Calculate -\frac{3}{2} to the power of 3 and get -\frac{27}{8}.

$$-\frac{19}{12}\left(-\frac{27}{8}\right)-2$$

Multiply -\frac{19}{12} and -\frac{27}{8} to get \frac{171}{32}.

$$\frac{171}{32}-2$$

Subtract 2 from \frac{171}{32} to get \frac{107}{32}.

$$\frac{107}{32}$$

Factor

$$\frac{107}{2 ^ {5}} = 3\frac{11}{32} = 3.34375$$