Solve (-2+8b)(6b-10)-48b^2+83b-19=0

$$( - 2 + 8 b ) ( 6 b - 10 ) - 48 b ^ { 2 } + 83 b - 19 = 0$$

Solve for b

$$b=\frac{1}{9}\approx 0.111111111$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2+8b by 6b-10 and combine like terms.

$$-92b+20+48b^{2}-48b^{2}+83b-19=0$$

Combine 48b^{2} and -48b^{2} to get 0.

$$-92b+20+83b-19=0$$

Combine -92b and 83b to get -9b.

$$-9b+20-19=0$$

Subtract 19 from 20 to get 1.

$$-9b+1=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-9b=-1$$

Divide both sides by -9.

$$b=\frac{-1}{-9}$$

Fraction \frac{-1}{-9} can be simplified to \frac{1}{9} by removing the negative sign from both the numerator and the denominator.

$$b=\frac{1}{9}$$