Solve (-10)^2+10^0+10^-2*(-10)^-2

$$( - 10 ) ^ { 2 } + 10 ^ { 0 } + 10 ^ { - 2 } \times ( - 10 ) ^ { - 2 }$$

Evaluate

$$\frac{1010001}{10000}=101.0001$$

Solution Steps

Calculate -10 to the power of 2 and get 100.

$$100+10^{0}+10^{-2}\left(-10\right)^{-2}$$

Calculate 10 to the power of 0 and get 1.

$$100+1+10^{-2}\left(-10\right)^{-2}$$

Add 100 and 1 to get 101.

$$101+10^{-2}\left(-10\right)^{-2}$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$101+\frac{1}{100}\left(-10\right)^{-2}$$

Calculate -10 to the power of -2 and get \frac{1}{100}.

$$101+\frac{1}{100}\times \frac{1}{100}$$

Multiply \frac{1}{100} and \frac{1}{100} to get \frac{1}{10000}.

$$101+\frac{1}{10000}$$

Add 101 and \frac{1}{10000} to get \frac{1010001}{10000}.

$$\frac{1010001}{10000}$$

Factor

$$\frac{3 \cdot 336667}{2 ^ {4} \cdot 5 ^ {4}} = 101\frac{1}{10000} = 101.0001$$