Solve (-1)^4-(-3)*(-1/3)+(-6)div1/2

$$( - 1 ) ^ { 4 } - ( - 3 ) \times ( - \frac { 1 } { 3 } ) + ( - 6 ) \div \frac { 1 } { 2 }$$

Evaluate

$$-12$$

Solution Steps

Calculate -1 to the power of 4 and get 1.

$$1-\left(-3\left(-\frac{1}{3}\right)\right)+\frac{-6}{\frac{1}{2}}$$

Multiply -3 times -\frac{1}{3}.

$$1-1+\frac{-6}{\frac{1}{2}}$$

Subtract 1 from 1 to get 0.

$$0+\frac{-6}{\frac{1}{2}}$$

Divide -6 by \frac{1}{2} by multiplying -6 by the reciprocal of \frac{1}{2}.

$$0-6\times 2$$

Multiply -6 and 2 to get -12.

$$0-12$$

Subtract 12 from 0 to get -12.

$$-12$$

Factor

$$-12$$