Solve (-1)^3-3^2+3*(-1)*3^2-3*(-1)^2*3

$$( - 1 ) ^ { 3 } - 3 ^ { 2 } + 3 \cdot ( - 1 ) \cdot 3 ^ { 2 } - 3 \cdot ( - 1 ) ^ { 2 } \cdot 3$$

Evaluate

$$-46$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\left(-1\right)^{3}-3^{2}+3^{3}\left(-1\right)-3\left(-1\right)^{2}\times 3$$

Calculate -1 to the power of 3 and get -1.

$$-1-3^{2}+3^{3}\left(-1\right)-3\left(-1\right)^{2}\times 3$$

Calculate 3 to the power of 2 and get 9.

$$-1-9+3^{3}\left(-1\right)-3\left(-1\right)^{2}\times 3$$

Subtract 9 from -1 to get -10.

$$-10+3^{3}\left(-1\right)-3\left(-1\right)^{2}\times 3$$

Calculate 3 to the power of 3 and get 27.

$$-10+27\left(-1\right)-3\left(-1\right)^{2}\times 3$$

Multiply 27 and -1 to get -27.

$$-10-27-3\left(-1\right)^{2}\times 3$$

Subtract 27 from -10 to get -37.

$$-37-3\left(-1\right)^{2}\times 3$$

Calculate -1 to the power of 2 and get 1.

$$-37-3\times 1\times 3$$

Multiply 3 and 1 to get 3.

$$-37-3\times 3$$

Multiply 3 and 3 to get 9.

$$-37-9$$

Subtract 9 from -37 to get -46.

$$-46$$

Factor

$$-46$$