Solve (-11/4)+(-2/3)+(+1/4)

$$( - 1 \frac { 1 } { 4 } ) + ( - \frac { 2 } { 3 } ) + ( + \frac { 1 } { 4 } )$$

Evaluate

$$-\frac{5}{3}\approx -1.666666667$$

Solution Steps

Multiply 1 and 4 to get 4.

$$-\frac{4+1}{4}-\frac{2}{3}+\frac{1}{4}$$

Add 4 and 1 to get 5.

$$-\frac{5}{4}-\frac{2}{3}+\frac{1}{4}$$

Least common multiple of 4 and 3 is 12. Convert -\frac{5}{4} and \frac{2}{3} to fractions with denominator 12.

$$-\frac{15}{12}-\frac{8}{12}+\frac{1}{4}$$

Since -\frac{15}{12} and \frac{8}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-15-8}{12}+\frac{1}{4}$$

Subtract 8 from -15 to get -23.

$$-\frac{23}{12}+\frac{1}{4}$$

Least common multiple of 12 and 4 is 12. Convert -\frac{23}{12} and \frac{1}{4} to fractions with denominator 12.

$$-\frac{23}{12}+\frac{3}{12}$$

Since -\frac{23}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{-23+3}{12}$$

Add -23 and 3 to get -20.

$$\frac{-20}{12}$$

Reduce the fraction \frac{-20}{12} to lowest terms by extracting and canceling out 4.

$$-\frac{5}{3}$$

Factor

$$-\frac{5}{3} = -1\frac{2}{3} = -1.6666666666666667$$