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1-2i\sqrt{3}-\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(-1+i\sqrt{3}\right)^{2}.
1-2i\sqrt{3}-3
The square of \sqrt{3} is 3.
-2-2i\sqrt{3}
Subtract 3 from 1 to get -2.
1-2i\sqrt{3}-\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(-1+i\sqrt{3}\right)^{2}.
1-2i\sqrt{3}-3
The square of \sqrt{3} is 3.
-2-2i\sqrt{3}
Subtract 3 from 1 to get -2.