Solve (-03)ab^4(+5/3)2(-b)a^3=

$$( - 03 ) a b ^ { 4 } ( + \frac { 5 } { 3 } ) 2 ( - b ) a ^ { 3 } =$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$0\times 3a^{4}b^{4}\times \frac{5}{3}\times 2\left(-b\right)$$

Multiply 0 and 3 to get 0.

$$0a^{4}b^{4}\times \frac{5}{3}\times 2\left(-b\right)$$

Multiply 0 and \frac{5}{3} to get 0.

$$0a^{4}b^{4}\times 2\left(-b\right)$$

Multiply 0 and 2 to get 0.

$$0a^{4}b^{4}\left(-b\right)$$

Anything times zero gives zero.

$$0$$

Factor

$$0$$