Solve (-6m^-4/n^2)*n^-2/3m^-3

$$( - \frac { 6 m ^ { - 4 } } { n ^ { 2 } } ) \times \frac { n ^ { - 2 } } { 3 m ^ { - 3 } }$$

Evaluate

$$-\frac{2}{mn^{4}}$$

Solution Steps

Multiply -\frac{6m^{-4}}{n^{2}} times \frac{n^{-2}}{3m^{-3}} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-6m^{-4}n^{-2}}{n^{2}\times 3m^{-3}}$$

Cancel out 3 in both numerator and denominator.

$$\frac{-2m^{-4}n^{-2}}{m^{-3}n^{2}}$$

To divide powers of the same base, subtract the numerator's exponent from the denominator's exponent.

$$\frac{-2}{m^{1}n^{4}}$$

Calculate m to the power of 1 and get m.

$$\frac{-2}{mn^{4}}$$

Differentiate w.r.t. m

$$\frac{2}{m^{2}n^{4}}$$