Solve (-2/3)^3*(2/3)^-2*(-2/3)^0=

$$( - \frac { 2 } { 3 } ) ^ { 3 } \times ( \frac { 2 } { 3 } ) ^ { - 2 } \times ( - \frac { 2 } { 3 } ) ^ { 0 } =$$

Evaluate

$$-\frac{2}{3}\approx -0.666666667$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 0 to get 3.

$$\left(-\frac{2}{3}\right)^{3}\times \left(\frac{2}{3}\right)^{-2}$$

Calculate -\frac{2}{3} to the power of 3 and get -\frac{8}{27}.

$$-\frac{8}{27}\times \left(\frac{2}{3}\right)^{-2}$$

Calculate \frac{2}{3} to the power of -2 and get \frac{9}{4}.

$$-\frac{8}{27}\times \frac{9}{4}$$

Multiply -\frac{8}{27} and \frac{9}{4} to get -\frac{2}{3}.

$$-\frac{2}{3}$$

Factor

$$-\frac{2}{3} = -0.6666666666666666$$