Solve (-2/3)^3+(10/8)^0-1^100+(3/6)=

$$( - \frac { 2 } { 3 } ) ^ { 3 } + ( \frac { 10 } { 8 } ) ^ { 0 } - 1 ^ { 100 } + ( \frac { 3 } { 6 } ) =$$

Evaluate

$$\frac{11}{54}\approx 0.203703704$$

Solution Steps

Calculate -\frac{2}{3} to the power of 3 and get -\frac{8}{27}.

$$-\frac{8}{27}+\left(\frac{10}{8}\right)^{0}-1^{100}+\frac{3}{6}$$

Reduce the fraction \frac{10}{8} to lowest terms by extracting and canceling out 2.

$$-\frac{8}{27}+\left(\frac{5}{4}\right)^{0}-1^{100}+\frac{3}{6}$$

Calculate \frac{5}{4} to the power of 0 and get 1.

$$-\frac{8}{27}+1-1^{100}+\frac{3}{6}$$

Add -\frac{8}{27} and 1 to get \frac{19}{27}.

$$\frac{19}{27}-1^{100}+\frac{3}{6}$$

Calculate 1 to the power of 100 and get 1.

$$\frac{19}{27}-1+\frac{3}{6}$$

Subtract 1 from \frac{19}{27} to get -\frac{8}{27}.

$$-\frac{8}{27}+\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{8}{27}+\frac{1}{2}$$

Add -\frac{8}{27} and \frac{1}{2} to get \frac{11}{54}.

$$\frac{11}{54}$$

Factor

$$\frac{11}{2 \cdot 3 ^ {3}} = 0.2037037037037037$$