Solve (-2/2-4*2)-(-5^2/2-4*5)

$$( - \frac { 2 } { 2 } - 4 \times 2 ) - ( - \frac { 5 ^ { 2 } } { 2 } - 4 \times 5 )$$

Evaluate

$$\frac{47}{2}=23.5$$

Solution Steps

Divide 2 by 2 to get 1.

$$-1-4\times 2-\left(-\frac{5^{2}}{2}-4\times 5\right)$$

Multiply 4 and 2 to get 8.

$$-1-8-\left(-\frac{5^{2}}{2}-4\times 5\right)$$

Subtract 8 from -1 to get -9.

$$-9-\left(-\frac{5^{2}}{2}-4\times 5\right)$$

Calculate 5 to the power of 2 and get 25.

$$-9-\left(-\frac{25}{2}-4\times 5\right)$$

Multiply 4 and 5 to get 20.

$$-9-\left(-\frac{25}{2}-20\right)$$

Convert 20 to fraction \frac{40}{2}.

$$-9-\left(-\frac{25}{2}-\frac{40}{2}\right)$$

Since -\frac{25}{2} and \frac{40}{2} have the same denominator, subtract them by subtracting their numerators.

$$-9-\frac{-25-40}{2}$$

Subtract 40 from -25 to get -65.

$$-9-\left(-\frac{65}{2}\right)$$

The opposite of -\frac{65}{2} is \frac{65}{2}.

$$-9+\frac{65}{2}$$

Convert -9 to fraction -\frac{18}{2}.

$$-\frac{18}{2}+\frac{65}{2}$$

Since -\frac{18}{2} and \frac{65}{2} have the same denominator, add them by adding their numerators.

$$\frac{-18+65}{2}$$

Add -18 and 65 to get 47.

$$\frac{47}{2}$$

Factor

$$\frac{47}{2} = 23\frac{1}{2} = 23.5$$