Solve (-1/4)^3*(-6^2)div11/2

$$( - \frac { 1 } { 4 } ) ^ { 3 } \times ( - 6 ^ { 2 } ) \div 1 \frac { 1 } { 2 }$$

Evaluate

$$\frac{3}{8}=0.375$$

Solution Steps

Calculate -\frac{1}{4} to the power of 3 and get -\frac{1}{64}.

$$\frac{-\frac{1}{64}\left(-6^{2}\right)}{\frac{1\times 2+1}{2}}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{-\frac{1}{64}\left(-36\right)}{\frac{1\times 2+1}{2}}$$

Express -\frac{1}{64}\left(-36\right) as a single fraction.

$$\frac{\frac{-\left(-36\right)}{64}}{\frac{1\times 2+1}{2}}$$

Multiply -1 and -36 to get 36.

$$\frac{\frac{36}{64}}{\frac{1\times 2+1}{2}}$$

Reduce the fraction \frac{36}{64} to lowest terms by extracting and canceling out 4.

$$\frac{\frac{9}{16}}{\frac{1\times 2+1}{2}}$$

Multiply 1 and 2 to get 2.

$$\frac{\frac{9}{16}}{\frac{2+1}{2}}$$

Add 2 and 1 to get 3.

$$\frac{\frac{9}{16}}{\frac{3}{2}}$$

Divide \frac{9}{16} by \frac{3}{2} by multiplying \frac{9}{16} by the reciprocal of \frac{3}{2}.

$$\frac{9}{16}\times \frac{2}{3}$$

Multiply \frac{9}{16} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 2}{16\times 3}$$

Do the multiplications in the fraction \frac{9\times 2}{16\times 3}.

$$\frac{18}{48}$$

Reduce the fraction \frac{18}{48} to lowest terms by extracting and canceling out 6.

$$\frac{3}{8}$$

Factor

$$\frac{3}{2 ^ {3}} = 0.375$$