Solve (-1/3)div(-1/0.9)div(-2/7)

$$( - \frac { 1 } { 3 } ) \div ( - \frac { 1 } { 0.9 } ) \div ( - \frac { 2 } { 7 } )$$

Evaluate

$$-1.05$$

Solution Steps

Divide \frac{-\frac{1}{3}}{-\frac{1}{0.9}} by -\frac{2}{7} by multiplying \frac{-\frac{1}{3}}{-\frac{1}{0.9}} by the reciprocal of -\frac{2}{7}.

$$\frac{-\frac{1}{3}\times 7}{\left(-\frac{1}{0.9}\right)\left(-2\right)}$$

Express -\frac{1}{3}\times 7 as a single fraction.

$$\frac{\frac{-7}{3}}{\left(-\frac{1}{0.9}\right)\left(-2\right)}$$

Fraction \frac{-7}{3} can be rewritten as -\frac{7}{3} by extracting the negative sign.

$$\frac{-\frac{7}{3}}{\left(-\frac{1}{0.9}\right)\left(-2\right)}$$

Expand \frac{1}{0.9} by multiplying both numerator and the denominator by 10.

$$\frac{-\frac{7}{3}}{-\frac{10}{9}\left(-2\right)}$$

Express -\frac{10}{9}\left(-2\right) as a single fraction.

$$\frac{-\frac{7}{3}}{\frac{-10\left(-2\right)}{9}}$$

Multiply -10 and -2 to get 20.

$$\frac{-\frac{7}{3}}{\frac{20}{9}}$$

Divide -\frac{7}{3} by \frac{20}{9} by multiplying -\frac{7}{3} by the reciprocal of \frac{20}{9}.

$$-\frac{7}{3}\times \frac{9}{20}$$

Multiply -\frac{7}{3} times \frac{9}{20} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-7\times 9}{3\times 20}$$

Do the multiplications in the fraction \frac{-7\times 9}{3\times 20}.

$$\frac{-63}{60}$$

Reduce the fraction \frac{-63}{60} to lowest terms by extracting and canceling out 3.

$$-\frac{21}{20}$$

Factor

$$-1.05$$